hi,
i have a parallelogram which is made up of of co ordinates which are, A(2,1) B(8.9) C(12,9) D(6,1):
i have drawn the shape but i don't know how to work out the area and perimeter of it so i was looking for some help please.
thanks!
hi,
i have a parallelogram which is made up of of co ordinates which are, A(2,1) B(8.9) C(12,9) D(6,1):
i have drawn the shape but i don't know how to work out the area and perimeter of it so i was looking for some help please.
thanks!
The perimeter is easy- it is twice the size of the lengths of two adjacent sides. AB and AD are two such sides: their lengths are $\displaystyle \sqrt{(8- 2)^2+ (9- 1)^2}$ and $\displaystyle \sqrt{(6- 2)^2+ (1-1)^2}$.
The area of a parallelogram is "height times base". Fortunately two of the parallel sides are "horizontal"- parallel to the x-axis. The length of the base AD is the difference in x coordinates of A and D:6- 2= 4. The height is the difference in y-coordinates: 9- 1= 8.
Hi andyboy179,
You have drawn this shape on a grid and you should be able to find the lengths of the sides and you id a 4. So what is the length of a longer side,With this the perimeter is easy. Just add the four sides.You may be hung up on area so go back to your book or to internet to find out how to calculate area.The numbers are right there on your grid.
bjh