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Thread: Helix / Spring Volume

  1. #1
    Aug 2007

    Helix / Spring Volume

    Hello, I need some help learning how to calculate the volume of a Spring. The only resource i can find is on wikipedia, but i am having trouble understanding it.

    Please see : Spring (mathematics) - Wikipedia, the free encyclopedia

    This is the forumula they give.

    R is the distance from the center of the tube to the center of the helix,
    r is the radius of the tube,
    P is the speed of the movement along the z axis.
    Ok, the helix will be 400 wide, so R = 200 units.
    The radius of the tube will be 30, so r = 30 units.

    Now this is where im stuck, they ask for P for the speed it moves upwards / downwards. How should i get this? For example if i want my spring to have 2 complete revolutions and have a total height of 500 units, how should i know what P is?

    I also need to know n, which is not explained very well what n is on the page.

    Many thanks if you can help me understand.
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  2. #2
    Eater of Worlds
    galactus's Avatar
    Jul 2006
    Chaneysville, PA
    Your helix has radius 200 and the tubing as radius 30. Correct?. This conflicts with R which says they're both 200.

    In this event R+r=230. That's what I'll use.

    Assume you're wrapping a tube of radius 30 around a helix of radius 200,

    This forms a helix. A helix can be represented by x=acos(t), \;\ y=asin(t), \;\ z=ct

    a in this case is R+r=230. The radius of the helix + radius of tubing.

    Since you want two revolutions when z=500 units, you have c=\frac{500}{4\pi}=\frac{125}{\pi}

    You have the helix: (230cos(t))i+(230sin(t))j+(\frac{125}{\pi}t)k

    It's length in making two revs in a distance of 500 units is given by

    2\pi\sqrt{230^{2}+(\frac{125}{\pi})^{2}}\approx{14  66.6}

    Now, this is a cylinder of radius 30 with height 1466.6

    {\pi}900(1466.6)=4,146,713.8 \;\

    Check my calculations out.
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  3. #3
    Aug 2007
    Wow thanks for taking the time to explain that to me more clearly.

    Hopefully your message will help others aswell if they find this through a search engine.
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