# Thread: Something wrong with this rhombus coordination

1. ## Something wrong with this rhombus coordination

hello Guys i think i have an error with my Coordinations here for a project. ( I believe i wrote it down) I found all the length are congruent but when I am trying to find all sides one of them is 10/4 instead of 4/10 IDK what to do.

( Coordinates here)

2. Originally Posted by vaironxxrd
( Coordinates here)
Coordinates WHERE?

3. Originally Posted by Wilmer
Coordinates WHERE?
CASH, C=(2,3) A=(6,13) S=(16,17) h=(12,7)

Sorry for that

4. exactly what are you asking us?

i checked one of the distances and got 10.77, not 10/4 or 4/10.

eg, CA:
$CA = \sqrt{(2-6)^2 + (3-13)^2)}$
$CA = \sqrt{(-4)^2 + (-10)^2)}$
$CA = \sqrt{116}$
$CA = 10.77....$

5. Originally Posted by vaironxxrd
hello Guys i think i have an error with my Coordinations here for a project. ( I believe i wrote it down) I found all the length are congruent but when I am trying to find all sides one of them is 10/4 instead of 4/10.
Same thing (DO NOT show as 10/4 or 4/10):
4 and 10 : sqrt(16 + 100) = sqrt(116)
10 and 4 : sqrt(100 + 16) = sqrt(116)

6. Hello, vaironxxrd!

$C(2,3),\;A(6,13),\;S(16,17),\;H(12,7)$

With answers like $\frac{10}{4}$ and $\frac{4}{10}$,
. . you are obviously determining the slopes of the sides.

But why?

What was the original question?

7. Hi vaironxxrd,
Were you asked to prove that the four point formed a rhombus? If so you did well.All four sides have. the right slopes proving that opposite sides are parallel.The slope diagrams are congruent so the lines are all equal.You were a little confused at the end but you do not have to show the length rad 116 for the sides

bjh