Hey,

Need a hint for this one. I feel I am missing something simple.

Triangle ABP is mapped onto triangle ABQ by a shear. The lines BP and AQ intersect at C. Given that BC:CP = 1:3, and that the area of triangle ACB is 2 sq. cm, find the area of,

(a) Triangle ACP,

(b) Triangle CPQ

(c) Quadrilateral ABQP

I have solved part B, using similar triangles, and ratio of area to square of corresponding sides, to get 18 sq cm.

But I am foggy on the parts (b) and (c). I see that Triangle ABP and Triangle ABQ have the same area, under a shear transform with shear factor 3. How to proceed further?

Thanks.