http://www.haeseandharris.com.au/sam...a11gt-5_02.pdf
PLEASE HELP ME!
Can you go to this link and go to chapter 2, page 89 question 7. I really really need help with this question, I know how to parts a and b, but i need help with c!!
THANKS!
xx
http://www.haeseandharris.com.au/sam...a11gt-5_02.pdf
PLEASE HELP ME!
Can you go to this link and go to chapter 2, page 89 question 7. I really really need help with this question, I know how to parts a and b, but i need help with c!!
THANKS!
xx
What did you get in b? The correct answer is $\displaystyle b$, i.e., the same as the x-coordinate of R. This means that RS is perpendicular to OB.
If you did not get the answer $\displaystyle b$ in b, then what are the equations of the perpendicular bisectors you got in a?
The x-coordinate of both R and S is b. This means that RS is vertical, i.e., perpendicular to OB. If this is not what you think is expected, then could you explain the definition of "perpendicular" that you use and the way you showed that some lines are perpendicular in your course?
Hello Tessarina,
S is the intersection of the perpendicular bisectors of two sides.It is therefore the circumcenter of circum scribed circle of triangle.All points from S to vertices are equal S lies on the perpendicular bisector of base.M the midpoint of base lies on the same line
bjh