How do you find the area of a triangle with side lengths of 8, 10, and 12? Reply within 24 hours after midnight tomorrow, I will go to bed so don't bother.
Anyways, help please!
One word "Heron's formula" - Oh that's two words.Originally Posted by extreme_pi
Let $\displaystyle s$ be the semi-perimeter of a triangle with sides $\displaystyle a$, $\displaystyle b$ and $\displaystyle c$, that is:
$\displaystyle s=\frac{a+b+c}{2}$.
Then area of the triangle is:
$\displaystyle \mbox{Area}=\sqrt{s(s-a)(s-b)(s-c)}$.
So in your case $\displaystyle s=\frac{8+10+12}{2}=15$ and so:
$\displaystyle \mbox{Area}=\sqrt{15(15-8)(15-10)(15-12)}\approx140.7$.
RonL
PS
You won't get banned for posting the same question multiple times, but the
duplicates will be deleted. This is so that people do not waste their time
answering questions already answered elsewhere.