Guys i don't understand this concept very well, please correct me.
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I prefer to think of it as an equilateral triangle which has been bisected - the image above is one of those halves.
Given that an equilateral triangle has angle 60 degrees and (in this case) side 5 then it follows that side a is half the length it was before being bisected, in other words
If then b can be found with Pythagoras theorem.
edit: it's even easier if you're allowed to use trig
Ah, I didn't see the ratio clearly first time around. Your working looks fine, what don't you understand?
The ratio given is
Your ratio is
The component parts must also be equal:
Once you've found x you can sub it into the first two parts to find a and b
My teacher explained to me if the hypotenuse is a whole number we gotta solve. But if it is the short leg ( For 60-30-90) Then we just place X and we are done.. Is this right or did i understand wrong?
Thing is he explains different from every explanations i see online.