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Math Help - Don't know which direction to go on this problem.

  1. #1
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    Question Don't know which direction to go on this problem.

    Suppose triangle ABC is an acute angle triangle. Let the bases of the altitudes to B and C be E and F, respectively, and let A' be the midpoint of BC. Prove that triangle A'EF is isosceles.

    Don't know how to start this one. Would the Euler Line come into play?
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  2. #2
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    A' is the mid point of BC.

     \angle{BFC} = \angle{BEC} = 90^o

    So BFEDC is a cyclic quadrilateral. Then .....?
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  3. #3
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    Quote Originally Posted by sa-ri-ga-ma View Post
    A' is the mid point of BC.

     \angle{BFC} = \angle{BEC} = 90^o

    So BFEDC is a cyclic quadrilateral. Then .....?
    Did you mean BFEC is a cyclic quadrilateral? If so, how did you get that?
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  4. #4
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  5. #5
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    Quote Originally Posted by Wilmer View Post
    Got it!! Thanks again!!
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