# Math Help - Don't know which direction to go on this problem.

1. ## Don't know which direction to go on this problem.

Suppose triangle ABC is an acute angle triangle. Let the bases of the altitudes to B and C be E and F, respectively, and let A' be the midpoint of BC. Prove that triangle A'EF is isosceles.

Don't know how to start this one. Would the Euler Line come into play?

2. A' is the mid point of BC.

$\angle{BFC} = \angle{BEC} = 90^o$

So BFEDC is a cyclic quadrilateral. Then .....?

3. Originally Posted by sa-ri-ga-ma
A' is the mid point of BC.

$\angle{BFC} = \angle{BEC} = 90^o$

So BFEDC is a cyclic quadrilateral. Then .....?
Did you mean BFEC is a cyclic quadrilateral? If so, how did you get that?

4. Originally Posted by Wilmer
Got it!! Thanks again!!