Here is one way that will work-- doubtless there are others.

1. Find the equation of the plane through ABC in the form f(x,y,z) = ax + by + cz = 0. I'm guessing you know how to compute a, b, and c. If not, let us know.

2. Compute f(D). In your example, that is 2a +2b + 2c.

3. Compute f(P) where P is your point of interest. In your example, that is 0a + 3b + 4c.

4. If the numbers computed in steps 2 and 3 have the same sign, then P and D lie on the same side of the plane ABC, so P may be inside the tetrahedron. If they don't have the same sign, P is definitely outside the tetrahedron.

5. If P passes the test (f(P) and f(D) have the same sign), repeat steps 1-4 for the other three faces of the tetrahedron: ABD, ACD, and BCD. If P passes the test for all the faces, it is inside the tetrahedron. That's because the tetrahedron is convex and is the intersection of the four half-spaces formed by the bounding planes.