hi, i need to find X and Y on this circle: i know X= 62 but im unsure how to work out what Y would be. could someone please explain how i would work this out! thanks!
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Originally Posted by andyboy179 find X and Y on this circle: i know X= 62 If you do know that $\displaystyle X=62$ then there is something wrong with your drawing. According to that drawing the central angle is 131 not 124.
sorry its my drawing, its not 131 its 31, i drew around the part which is 31
Originally Posted by andyboy179 sorry its my drawing, its not 131 its 31, i drew around the part which is 31 You have the wrong idea there. Look up inscribed angle and also centeral angles. Find out how their measures are found.
will do but i will just let you know why i thought it is 61. i thougt it was 61 because i thought that the X angle is alwas double whatever is where 31 is, so 31 x2=62
would x be 15.5 because the angle from center(31) is twice as big as circumferance.
Originally Posted by andyboy179 would x be 15.5 because the angle from center(31) is twice as big as circumferance. That is correct. So $\displaystyle y=\dfrac{360 - 2x}{2}.$
So Y=164.5??
So would this mean y=164.5??
hi, i need to work out what Y is on this circle theorem: to find Y would i do: 360-31= 329 329/2=164.5 Y=164.5
Originally Posted by andyboy179 hi, i need to work out what Y is on this circle theorem: to find Y would i do: 360-31= 329 329/2=164.5 Y=164.5 Hi andyboy179, Your answer is correct. y = 164.5 degrees
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