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**DivideBy0** *In a regular polygon there are two diagonals such that the angle between them is 50 degrees. What is the smallest number of sides of the polygon for which this is possible?*

I had thought that for this to be the case, the smallest possible angle between diagonals of a polygon must be a factor of 50.

Factors of 50: 1, 50, 2, 25, 5, 10

Let x be the number of sides of the polygon

The biggest factor that lets x be a whole number is 10.

$\displaystyle \frac{360}{x}= 10$

$\displaystyle x=36$

**WRONG!**

Answer is 18.