Thread: more urgent areas and ratios

1. more urgent areas and ratios

2. Originally Posted by sanee66
To A

the area of the rhombus is $4 \times _{area} \triangle UMW$

to find the area of the triangle use the $\frac {1}{2} \cdot base \cdot height$ formula (note, you have to find the height, use Pythagoras' theorem

got it?

do you know what a rhombus is? do you know the properties of a rhombus? see here

questions become easier when you know what you are dealing with

3. Originally Posted by sanee66
B is $81 \sqrt {3}$

but i think that's what you meant to type... right?

double check question C. something is wrong with it

D is correct

clarify question E, what exactly is raised to the 4th power?

To F.

the circumference of a circle is given by:

$C = 2 \pi r$

For circle R, $12 \pi = 2 \pi r_R \implies \boxed { r_R = 6 }$

For circle S, $32 \pi = 2 \pi r_S \implies \boxed { r_S = 16 }$

Thus, the ratio of the radius of S to the radius of R is:

$r_S:r_R = \frac {r_S}{r_R} = \frac {16}{6} = \frac {8}{3} = 8:3$

4. Ratio of circumference of circle C to its radius is . Which is the area of the circle?
Should be one of these

5. Originally Posted by sanee66
Ratio of circumference of circle C to its radius is . Which is the area of the circle?
Should be one of these

it seems you have some images missing, i can't see them. do you know how to use LaTex?

6. 4pir4, I think the r is to the 4th and to the 6th for 16pir6.
I have no clue about latex and there are no images with the other question

Here is how it looks after finding the symbols
Area of circle P is 4πr4 and area of circle Q is16πr6. Which is the ratio of a radius of Q to a radius of P
The last 4 and the 6 are the powers and I think they go with the r.

7. Originally Posted by sanee66
4pir4, I think the r is to the 4th and to the 6th for 16pir6.
I have no clue about latex and there are no images with the other question

Here is how it looks after finding the symbols
[FONT='Times New Roman','serif']Area of circle P is 4πr4 and area of circle Q is16πr6. Which is the ratio of a radius of Q to a radius of P[/font]
you could type, the first one for instance, as 4*pi*r^4

doing that avoids confusion.

8. Originally Posted by sanee66
4pir4, I think the r is to the 4th and to the 6th for 16pir6.
I have no clue about latex and there are no images with the other question

Here is how it looks after finding the symbols
Area of circle P is 4πr4 and area of circle Q is16πr6. Which is the ratio of a radius of Q to a radius of P
The last 4 and the 6 are the powers and I think they go with the r.
here it is:

E

Recall that the area of a circle is given by $A = \pi r^2$

So, for P: $P_{area} = 4 \pi r^4$

$\Rightarrow 4 \pi r^4 = \pi r_P^2$

$\Rightarrow 4r^4 = r_P^2$

$\Rightarrow r_P = \sqrt {4 r^4} = 2r^2$

For Q: $Q_{area} = 16 \pi r^6$

$\Rightarrow 16 \pi r^6 = \pi r_Q^2$

$\Rightarrow 16r^6 = r_Q^2$

$\Rightarrow r_Q = \sqrt {16r^6} = 4r^3$

So the ratio of the radius of Q to the radius of P is:

$r_Q : r_P = \frac {r_Q}{r_P} = \frac {4r^3}{2r^2} = 2r$

9. I want to thank you so much for this. You are GREAT! That just leaves A and C and I have tried to get them. I don't have any images for C just what I posted and those are the answers I can choose from. I think when I am trying to use the P theorem, I am putting the numbers in the wrong place in the formula for A.

10. Originally Posted by sanee66
I want to thank you so much for this. You are GREAT! That just leaves A and C and I have tried to get them. I don't have any images for C just what I posted and those are the answers I can choose from. I think when I am trying to use the P theorem, I am putting the numbers in the wrong place in the formula for A.
i will look over C again and see if i can decipher what you want to say.

to A

see the diagram below:

Pythagoras theorem says: If the sides of a right-triangle have lengths $a$, $b$ and $c$, (where $c$ is the hypotenuse), then the sides can be related as follows:

$a^2 + b^2 = c^2$

In the triangle below, $c = 14$, $a = 10$, we want to find $b$ which is $x$ on the diagram.

$a^2 + b^2 = c^2$

$\Rightarrow b^2 = c^2 - a^2$

$\Rightarrow b = \sqrt { c^2 - b^2 }$

$\Rightarrow b = x = \sqrt {14^2 - 10^2} = \sqrt {96}$

So the area of the triangle is:

$A = \frac {1}{2}bh = \frac {1}{2} 10 \cdot \sqrt {96} = 5 \sqrt {96}$

the area of the rhombus is 4 times the area of one triangle.

so area of rhombus is: $A_R = 4 \times 5 \sqrt {96} = 20 \sqrt {96} = 80 \sqrt {6}$

11. the ratio of the circumference of ANY circle to it's radius is $2 \pi$ -- always. so your question simply makes no sense

12. The only answers I can choose for the answer to the area of the rhombus are
184.86
195.96
274.34
276.34

13. Originally Posted by sanee66
The only answers I can choose for the answer to the area of the rhombus are
184.86
195.96
274.34
276.34
it is 195.96

that's the answer i gave you--or should be the answer, maybe i simplified incorrectly, let me check

EDIT: yeah, my mistake. i forgot the 20 that was multiplying the 4*sqrt(6), i corrected it. the answer is 80*sqrt(6) = 195.96

14. Ratio of circumference of circle C to its radius is 12pi. Which is the area of the circle? 36pi,34pi,28pi, or 24pi
I found a place that says
The distance around a circle is called the circumference. The distance across a circle through the center is called the diameter. is the ratio of the circumference of a circle to the diameter. Thus, for any circle, if you divide the circumference by the diameter, you get a value close to .
C=2*pi*r
So 12pi=2*pi*r
Then what?

15. Originally Posted by sanee66
Ratio of circumference of circle C to its radius is 12pi. Which is the area of the circle? 36pi,34pi,28pi, or 24pi
I found a place that says
The distance around a circle is called the circumference. The distance across a circle through the center is called the diameter. is the ratio of the circumference of a circle to the diameter. Thus, for any circle, if you divide the circumference by the diameter, you get a value close to .
C=2*pi*r
So 12pi=2*pi*r
Then what?
ratio means divide, not equate. the ratio of a circumference of a circle to it's radius is $\frac {2 \pi r}{r} = 2 \pi$ always, $2 \pi$ cannot equal $12 \pi$ no matter what. so your question is off