In ABC, E and F are such that A-F-B and A-E-C. Segments BE and CF intersect at P. Area of PEC=4 and area of PFB=8 and area of PBC=10. Find the area of quadrilateral AFPE.
I tried using reallyyyy many many approaches, even basic-most properties, but i couldn't get to it.
Easy solution, once one realises this is a mini "crossing ladder" classic problem; go here:
Crossed Ladder Puzzle, Triangle Area Puzzle