In $\displaystyle \triangle$ABC, E and F are such that A-F-B and A-E-C. Segments BE and CF intersect at P. Area of $\displaystyle \triangle$PEC=4 and area of $\displaystyle \triangle$PFB=8 and area of $\displaystyle \triangle$PBC=10. Find the area of quadrilateral AFPE.

I tried using reallyyyy many many approaches, even basic-most properties, but i couldn't get to it. (Headbang)