What? Let's guess Mr. Zeus has a cubic alter?
If the original has volume a^3, the new one will need volume b^3 - a^3 = 2a^3 for some b. A little algebra suggests b^3 = 3a^3, which probably could have been guessed.
Make Zeus' altar double as big using equal parts of it enclosing a hollow altar of the original. What I have so far is-
Where a equals the divisor of a cube, so that if a = 2, the cube is divided into 8 parts, more straightforward that a is the number of squares along a side:
6a^2 + 12a + 8
A phrase in it which you will probably use in it. I have a lightning bolt of a headache and can't finish it.
where is the side of the new alter and the side of the original. But this is imposible since would have to be an rational multiple of and so imply that is rational