ABC is a triangle and the line YCX is parallel to AB such that AX and BY are the angle bisectors of A and B respectively.If AX meets BC at D and BY meets AC at E and if YE=XD prove that AC=BC.
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Alternate Interior Angles of a Transversal cutting two parallel lines
That's more than nothing and so far I used only one theorem!
that much i had. also AC=CX and CB=CY. but still i am stuck.
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