ABC is a triangle and the line YCX is parallel to AB such that AX and BY are the angle bisectors ofA and
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ABC is a triangle and the line YCX is parallel to AB such that AX and BY are the angle bisectors of
You've nothing?
Hints:
Alternate Interior Angles of a Transversal cutting two parallel lines
That's more than nothing and so far I used only one theorem!
that much i had. also AC=CX and CB=CY. but still i am stuck.