# angle bisector problem

• February 11th 2011, 05:35 PM
abhishekkgp
angle bisector problem
ABC is a triangle and the line YCX is parallel to AB such that AX and BY are the angle bisectors of $\angle$A and $\angle$B respectively.If AX meets BC at D and BY meets AC at E and if YE=XD prove that AC=BC.
• February 11th 2011, 07:37 PM
TKHunny
You've nothing?

Hints:

Alternate Interior Angles of a Transversal cutting two parallel lines

$m\angle X = \frac{1}{2} m\angle A$

$m\angle Y = \frac{1}{2} m\angle B$

$m\angle ACY = m\angle A$

$m\angle BCX = m\angle B$

That's more than nothing and so far I used only one theorem!
• February 11th 2011, 09:11 PM
abhishekkgp
that much i had. also AC=CX and CB=CY. but still i am stuck.