Prove that if $\displaystyle D$ is internal to $\displaystyle \overline{AB}$, $\displaystyle E$ is internal to $\displaystyle \overline{AC}$ and $\displaystyle \frac{DB}{ DA} = \frac{EC}{EA}$ then $\displaystyle {BC}$ is parallel to $\displaystyle {DE}$

I'm having a tough time figuring out where to start or how to go about doing this proof, we've been focusing on Ceva's theorem as of late so I'm thinking I have to incorporate it some how.