Results 1 to 4 of 4
Like Tree1Thanks
  • 1 Post By skeeter

Thread: How to find cylinder dimensions from volume and aspect ratio?

  1. #1
    Newbie
    Joined
    Feb 2011
    Posts
    1

    How to find cylinder dimensions from volume and aspect ratio?

    Okay, so basically what I'm trying to figure out is how to find the dimensions (length and diameter) of a cylinder when I know the volume and the ratio of length to diameter (for instance, a cylinder x times longer than it is wide). Unfortunately, I haven't been able to figure out how to do so on my own and google hasn't exactly been helpful. I'm quite stumped, so I would greatly appreciate any help.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    12,811
    Thanks
    1921
    I expect when you say length you mean height...

    You should know that \displaystyle V = \pi r^2 h.

    If you know the ratio of height to diameter/radius, you'll be able to substitute it into the volume equation and solve for one of the variables.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Feb 2017
    From
    Arizona
    Posts
    1

    Re: How to find cylinder dimensions from volume and aspect ratio?

    I have a similar problem. Diameter=height, Volume = 50m^3
    so... r=D2 and h=D
    V=pi*h*r^2
    V=pi*D*(D/2)^2
    V/pi=D*(D/2)^2

    PEMDAS is confusing me, can I...

    V/pi=D*(D/2)*(D/2)
    V/pi=D^3 / 4
    ?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    15,876
    Thanks
    3524

    Re: How to find cylinder dimensions from volume and aspect ratio?

    Quote Originally Posted by mstngofire View Post
    I have a similar problem. Diameter=height, Volume = 50m^3
    so... r=D2 and h=D
    V=pi*h*r^2
    V=pi*D*(D/2)^2
    V/pi=D*(D/2)^2

    PEMDAS is confusing me, can I...

    V/pi=D*(D/2)*(D/2)
    V/pi=D^3 / 4
    ?
    $d^3 = \dfrac{4V}{\pi}$

    $d = \sqrt[3]{\dfrac{4V}{\pi}}$
    Thanks from mstngofire
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: Apr 15th 2010, 10:58 PM
  2. h of cylinder, given volume and h->r ratio
    Posted in the Geometry Forum
    Replies: 1
    Last Post: Feb 19th 2010, 10:59 AM
  3. Replies: 1
    Last Post: Mar 14th 2009, 09:34 PM
  4. Replies: 3
    Last Post: Mar 14th 2009, 09:24 PM
  5. resize x maintain y aspect ratio
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 13th 2008, 10:05 AM

Search tags for this page

Search Tags


/mathhelpforum @mathhelpforum