Hello A triangle has one side that is 7 and another side that is 12. What it the max and min value for the third side. Thank you for any help
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Originally Posted by Makron Hello A triangle has one side that is 7 and another side that is 12. What it the max and min value for the third side. Thank you for any help If you know the law of cosines then $\displaystyle c^2=a^2+b^2-2ab\cos(\theta)$ $\displaystyle c^2=49+144-168\cos(\theta)$ Can you finish from here?
Thank you for helping =) but the angle is unknown ?
Originally Posted by Makron Hello A triangle has one side that is 7 and another side that is 12. What it the max and min value for the third side. Thank you for any help Hi Makron, If the third side is $\displaystyle x $, then $\displaystyle 5 < x < 19$ Essentially, the third side must be greater then the difference of the other two sides, but less than their sum.
thank you but I would like to know how to complete the ekvation that "Emptyset" posted
The equation was $\displaystyle c^2= 49+ 25- 168cos(\theta)$. The angle $\displaystyle \theta$ can be any angle between 0 and 180 degrees. What is that equation if $\displaystyle \theta= 0$? What if $\displaystyle \theta= 180$?
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