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Math Help - draw curve

  1. #1
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    draw curve

    need help with this one.

    draw the curve y^2=2x-1

    y=(2x-1)^0.5 x > 1/2

    ?
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  2. #2
    Senior Member yeKciM's Avatar
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    Quote Originally Posted by paulaa View Post
    need help with this one.

    draw the curve y^2=2x-1

    y=(2x-1)^0.5 x > 1/2

    ?
    and now just make you'r self table... and get 3 points chose x and get y ... and just connect them ... you have one there its y= 0 in x = 0.5 you need just 2 more
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  3. #3
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    do you mean like this:


    y x
    0 0.5
    1 1
    2 2.5

    and then ?
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  4. #4
    Senior Member yeKciM's Avatar
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    for x = 0.5 you have y = 0
    for x = 1 you have y = (2*1-1)^(1/2) = 1 and also y = -1

    so you have 3 points and now just connect them your curve goes from x = 0.5 to infinity or less :P so it's moving to the "right" above and belove x axis
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  5. #5
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    how do you know that it is to the right ?
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  6. #6
    Senior Member yeKciM's Avatar
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    Quote Originally Posted by paulaa View Post
    how do you know that it is to the right ?
    how in detail you need your answer ? Because i don't know for which level do I approach because this is simple curve (parabola) and some curve's like this you get to know .... y = x^2 , -y=x^2 , x = y^2 , -x = y^2 ... and all can be done by 3 points or more if you like and connecting them... but if you need to do , region for which function is defined , add or even or neither, sing , asymptote's , first and second derivate... we will do it different
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  7. #7
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    thz for the answers
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  8. #8
    Senior Member yeKciM's Avatar
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    you should know also that y = x^2 and y = x^2 -1 or y= x^2 +1 are the same parabola just shifted up or down, left or right depending on which do you have ... y = x^2 have zero in point (x=0,y=0) , and y = x^2 +1 looks the same but have zero in (x=0, y = 1) so it's just shifted upwards by the y axis play little and you will have no problem with this type of curves
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  9. #9
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    yes i did know that :P but thanks
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