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Math Help - Ratio 3 problem medium

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    Senior Member vaironxxrd's Avatar
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    Ratio 3 problem medium

    hello guys got stuck on my last exercise of ratio today, Is kind of easy but i don't know what steps to go for... i did read the book but im still confused

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    Quote Originally Posted by vaironxxrd View Post
    hello guys got stuck on my last exercise of ratio today, Is kind of easy but i don't know what steps to go for... i did read the book but im still confused

    \displaystyle\frac{1}{7}\cdot\frac{2}{x}=\frac{7}{  y}\cdot\frac{1}{7}\Rightarrow x\cdot\frac{2}{7x}=\frac{1}{y}\cdot x=\cdots
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    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    \displaystyle\frac{1}{7}\cdot\frac{2}{x}=\frac{7}{  y}\cdot\frac{1}{7}\Rightarrow x\cdot\frac{2}{7x}=\frac{1}{y}\cdot x=\cdots
    How did you got that [Math]\displaystyle\frac{1}{7}[/tex]
    The book Does not give me a 1
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    Quote Originally Posted by vaironxxrd View Post
    How did you got that [Math]\displaystyle\frac{1}{7}[/tex]
    The book Does not give me a 1
    Divide by 7.
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    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    Divide by 7.
    Sorry if ill keep asking the same question but is there any reason for this?
    i mean i got [Math]\frac{2}{7}\frac{?}{?}[/tex]
    So the equals sign say that we don't know that number so i believe it can be any number, You understand how im i getting confuse?
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    Quote Originally Posted by vaironxxrd View Post
    Sorry if ill keep asking the same question but is there any reason for this?
    i mean i got [Math]\frac{2}{7}\frac{?}{?}[/tex]
    So the equals sign say that we don't know that number so i believe it can be any number, You understand how im i getting confuse?
    \displaystyle\frac{2}{x}=\frac{7}{y}\cdot\frac{7}{  7}

    7/7 is 1, so we aren't doing anything to the equation by multiplying by 1.

    \displaystyle\frac{1}{7}\cdot\frac{2}{x}=\frac{7}{  y}\cdot\frac{1}{7}\Rightarrow\frac{2}{7x}=\frac{1}  {y}

    \displaystyle\frac{x}{x}\cdot\frac{2}{7x}=\frac{1}  {y}\Rightarrow x\cdot\frac{2}{7x}=x\cdot\frac{1}{y}

    x/x is 1 too so we didn't do anything to the equation.

    \displaystyle\frac{2}{7}=\frac{x}{y}
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    Ration

    OH that is the answer? Still confusing for me ! Oh i see some notes on this but it just does not match the problem
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    Quote Originally Posted by vaironxxrd View Post
    OH that is the answer? Still confusing for me ! Oh i see some notes on this but it just does not match the problem
    \displaystyle\frac{7}{7}=1

    Multiplying by doesn't change the equality. Same applies to x/x.

    I don't understand what you don't get. Can you be more specific?
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    Quote Originally Posted by dwsmith View Post
    \displaystyle\frac{7}{7}=1

    Multiplying by doesn't change the equality. Same applies to x/x.

    I don't understand what you don't get. Can you be more specific?
    Ok.. Sorry for that let me try to explain.

    I started with [Math]\frac{2}{X} = \frac{7}{y} Then \frac {2}{7} = \frac {?}{?}[/tex]
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    Quote Originally Posted by vaironxxrd View Post
    Ok.. Sorry for that let me try to explain.

    I started with [Math]\frac{2}{X} = \frac{7}{y} Then \frac {2}{7} = \frac {?}{?}[/tex]
    Then Post 6 shows the math progression.
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    Quote Originally Posted by vaironxxrd View Post
    Ok.. Sorry for that let me try to explain.

    I started with [Math]\frac{2}{X} = \frac{7}{y} Then \frac {2}{7} = \frac {?}{?}[/tex]
    so i believe THe result would be {2y}{7x}[/tex] because we are multiplying it?
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    Quote Originally Posted by vaironxxrd View Post
    so i believe THe result would be {2y}{7x}[/tex] because we are multiplying it?
    \displaystyle\frac{2}{x}=\frac{7}{y}\cdot\frac{7}{  7} \ \text{7 divided by 7 is 1 so we aren't changing the equality by multiplying by 1.}

    \displaystyle\frac{1}{7}\cdot\frac{2}{x}=\frac{7}{  y}\cdot\frac{1}{7} \ \text{lets prove this is the same as the above equation.}

    If we multiply both sides by 7, we will have 1 and 7/7.

    \displaystyle 7\cdot\frac{1}{7}\Rightarrow\frac{7}{7}\Rightarrow 1\cdot\frac{2}{x}=\frac{7}{y}\cdot\frac{1}{7}\cdot 7\Rightarrow\frac{2}{y}\cdot\frac{7}{7} \ \text{as you can see, the 7 on the left hand side back to the right.}

    Same for the x.
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    Quote Originally Posted by dwsmith View Post
    \displaystyle\frac{2}{x}=\frac{7}{y}\cdot\frac{7}{  7} \ \text{7 divided by 7 is 1 so we aren't changing the equality by multiplying by 1.}

    \displaystyle\frac{1}{7}\cdot\frac{2}{x}=\frac{7}{  y}\cdot\frac{1}{7} \ \text{lets prove this is the same as the above equation.}

    If we multiply both sides by 7, we will have 1 and 7/7.

    \displaystyle 7\cdot\frac{1}{7}\Rightarrow\frac{7}{7}\Rightarrow 1\cdot\frac{2}{x}=\frac{7}{y}\cdot\frac{1}{7}\cdot 7\Rightarrow\frac{2}{y}\cdot\frac{7}{7} \ \text{as you can see, the 7 on the left hand side back to the right.}

    Same for the x.
    oh ok thanks
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