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Math Help - Find the Area of the shaded sector [Basic]

  1. #1
    Senior Member vaironxxrd's Avatar
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    Find the Area of the shaded sector [Basic]

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  2. #2
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    The area of the entire circle is A=\pi r^2=16\pi

    \displaystyle\frac{120}{360}=\frac{1}{3}

    The shaded area is 1/3 of the circle.
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    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    The area of the entire circle is A=\pi r^2=16\pi

    \displaystyle\frac{120}{360}=\frac{1}{3}

    The shaded area is 1/3 of the circle.
    So you just simplify the fraction?
    Last edited by vaironxxrd; January 14th 2011 at 06:37 PM. Reason: Wrong grammar
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    Quote Originally Posted by vaironxxrd View Post
    So you just simplify the fraction?
    Just divide.

    \displaystyle\frac{16\pi}{3}
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    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    Just divide.

    \displaystyle\frac{16\pi}{3}
    1.04 .....
    A little confused understanding this concept.
    First how did you get it?( sorry for the annoying simple question)
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    Quote Originally Posted by vaironxxrd View Post
    1.04 .....
    A little confused understanding this concept.
    First how did you get it?( sorry for the annoying simple question)
    How would you find 1/2 of 100?
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  7. #7
    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    How would you find 1/2 of 100?
    hahahahaha,. 50
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    Quote Originally Posted by vaironxxrd View Post
    hahahahaha,. 50
    \displaystyle\frac{100}{2}

    Well 1/3 of 16\pi is \displaystyle\frac{16\pi}{3}
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    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    \displaystyle\frac{100}{2}

    Well 1/3 of 16\pi is \displaystyle\frac{16\pi}{3}
    or 0.333333333?
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  10. #10
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    That is 1/3.

    \displaystyle\frac{16\pi}{3}\approx 16.75516
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  11. #11
    Senior Member vaironxxrd's Avatar
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    Quote Originally Posted by dwsmith View Post
    That is 1/3.

    \displaystyle\frac{16\pi}{3}\approx 16.75516
    Oh now i get it
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