
sine and consine rules
A bird leaves a nest, N, and flies 800 m on a bearing of 132 degrees to a tree T. It then leaves T and flies 650 m on a bearing of 209 degrees to a pylon P. Assuming that N, T and P are at the same height above the ground, calculate the distance and bearing on which the bird must fly in order to return directly from P to N.
I need your help please ^
time: 2h+

Start by drawing the situation and marking in all known sides and angles.

the calculations are easy?

If you draw the diagram, you will have a triangle with 2 known sides and a known angle in between.
Law of cosines.

Provided you end up with a triangle that has enough known sides/angles in order to solve for the remaining ones, yes.


Sine Rule:
$\displaystyle \displaystyle \frac{a}{\sin{A}} = \frac{b}{\sin{B}} = \frac{c}{\sin{C}}$ or $\displaystyle \displaystyle \frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}$.
Cosine Rule:
$\displaystyle \displaystyle c^2 = a^2 + b^2  2ab\cos{C}$ or $\displaystyle \displaystyle \cos{C} = \frac{a^2 + b^2  c^2}{2ab}$.