Hello, John 5!

3.) A 2.05 m tall basketball player takes a shot 6.02 meters from the basket.

If the launch is 25° and the ball is launched at the level of the player's head,

what must the release speed of the ball for the player to make the shot?

The basket is 3.05 m above the floor.

We are expected to know the "trajectory equations":

. .

. .

. . . . where: .

We are given: .

We will let: .

Our equations are: .

And we want: .

Set [1] equal to 6.02: . .[3]

Set [2] equal to 1: .

Substitute [3]: .

We have: .

Then: .

Hence: .

. . And I got: . m/sec

A practical note:

This speed allows the ball to meet therimof the basket.

It does not guarentee a score.