Your arithmetic is off . . .
Values of two of the three expressions have not been set.
Decide these values.
Since is in Quadrant 4, is positive: .
values of two of the three expressions cos (x), sin (x), and tan (x), has not been set. Decide these values.
sin(x) = -((2)/(5^0.5)) , 3n/2<x<2n
cos(x)^2 + sin(x)^2 = 1
cos(x) = (1-sin(x)^2)^0.5 = (1-(-2/(5^0.5))^2)^0.5 = (9/5)^0.5
tan(x) = ((-2/(5^0.5))/((9/5)^0.5) = (-10^0.5)/5
When I leave it to my teacher I get error, does anyone know what the problem is? He says that you should show 3n/2<x<2n in sin, cos and tan in any way.
By n I mean pi