find a constant b such that f(x)=b
that divides the area between x-axis
and the function $\displaystyle g(x) = 9 - |x|$
into 2 equal eares.
oh ya !!!
Triangle1: has a right angle and 2 equal sides.
Triangle2: is the whole triangle.
area of Triangle1 $\displaystyle = \frac {(9-b)^2}{2}$
area of Triangle2 $\displaystyle = (\frac{1}{2}).(18).(9) = 81$
area of Triangle1 $\displaystyle = \frac{81}{4}$
Thank you very much.