find a constant b such that f(x)=b

that divides the area between x-axis

and the function $\displaystyle g(x) = 9 - |x|$

into 2 equal eares.

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- Dec 31st 2010, 01:42 PMrazemsoft21Find the equation of line that ....
find a constant b such that f(x)=b

that divides the area between x-axis

and the function $\displaystyle g(x) = 9 - |x|$

into 2 equal eares. - Dec 31st 2010, 02:37 PMPlato
Can you solve this, $\displaystyle \dfrac{(9-b)^2}{2}=\dfrac{81}{4}~?$

If so, how does that work? - Dec 31st 2010, 03:10 PMrazemsoft21
oh ya !!!

Triangle1: has a right angle and 2 equal sides.

Triangle2: is the whole triangle.

area of Triangle1 $\displaystyle = \frac {(9-b)^2}{2}$

area of Triangle2 $\displaystyle = (\frac{1}{2}).(18).(9) = 81$

area of Triangle1 $\displaystyle = \frac{81}{4}$

Thank you very much.