1. similiarities

Equilateral triangle abc is similar to the equilateral triangle fdr with the ratio of similarity 13. Which is equivalent to 3ab+5bc
6fd+7dr?

2. $AB=BC$ and $FD=DR$ and $\frac{AB}{FD}=13$.
Can you go on from here?

3. still need help

Ok but i thoought that looked like i would take 13 times the number in the equation but I am not coming up with any of the answers given me. Could you help a little more please?

4. $\frac{3AB+5BC}{6FD+7DR}=\frac{3AB+5AB}{6FD+7FD}=\f rac{8AB}{13FD}=\frac{8}{13}\cdot 13=8$