Have you tried drawing a line with A, B, C such that AB < AC and then trying to insert D so that BD < BC? I know it's just a restatement of the problem, but I don't see any difficulty in this problem other than trying a few cases.
Can anybody help me on this problem please.
For any points ABCD are arranged along a line such that AC>AB and BD<BC. Draw a picture with the four points in plane. Is there more than one order possible?
Thanks a lot
This is precisely why I asked for clarification as to exactly what is involved here. I assumed that this question has to do with ordering collinear points using some form of Hilbert’s betweenness axioms. If that is correct then there is only one possible order: .
There is no notion of a mirror image in the axioms.
Short of something like Ed Moise’s ruler axiom spacing makes no difference.
To be clear on what this means, given we know that .
BUT there is no way to compare , without knowing the full context of the question.