2(3x + 4) = 4x + 16 find x
2y = 1/2(3y + 5) find y
d + 2 = 1/2(4d - 6) find d
4q - 2 = 2(3q - 6) find q
Can someone offer help?
The idea of these problems is to get all of the unknown(in this case x) on one side and the numbers on the other.
Firstly , expand all the brackets.
This can be done by multiplying 2(the factor) into the bracket.
$\displaystyle = 6x + 8$ (nothing changes on the right side)
$\displaystyle 6x + 8 = 4x + 16 $
Now, 'move' the x to the left side and the 8 to the right side.
Subtract 8 and 4x from both sides.
$\displaystyle 6x +8 - 8 - 4x = 4x - 4x -8 + 16 $
$\displaystyle 2x = 8 $
$\displaystyle x = \dfrac{8}{2} = 4. $
Solve the other problems in the similar fashion. Hope this helps.