1. ## finding x

2(3x + 4) = 4x + 16 find x

2y = 1/2(3y + 5) find y

d + 2 = 1/2(4d - 6) find d

4q - 2 = 2(3q - 6) find q

Can someone offer help?

2. The Distributive law is used here. Can you expand the brackets?

3. Expand the brackets?

4. You should know that $\displaystyle a(b + c) = ab + ac$. See how what's on the outside has been multiplied by everything on the inside?

If you do that then that simplifies the problems greatly.

This is called "expanding the brackets".

2(3x + 4) = 4x + 16 find x
as mentioned your first step should look like this

$6x + 8 = 4x +16$

it easy from here

expanding the brackets means distribution

6. If the distributive law is not desired then as a first step for each

Q1. divide both sides by 2

Q2. times both sides by 2

Q3. times both sides by 2

Q1. divide both sides by 2

7. Originally Posted by pickslides
If the distributive law is not desired then as a first step for each

Q1. divide both sides by 2

Q2. times both sides by 2

Q3. times both sides by 2

Q1. divide both sides by 2
Even after doing this, you will still need to expand some brackets...

2(3x + 4) = 4x + 16 find x
The idea of these problems is to get all of the unknown(in this case x) on one side and the numbers on the other.
Firstly , expand all the brackets.
This can be done by multiplying 2(the factor) into the bracket.
$= 6x + 8$ (nothing changes on the right side)
$6x + 8 = 4x + 16$
Now, 'move' the x to the left side and the 8 to the right side.
Subtract 8 and 4x from both sides.
$6x +8 - 8 - 4x = 4x - 4x -8 + 16$
$2x = 8$
$x = \dfrac{8}{2} = 4.$

Solve the other problems in the similar fashion. Hope this helps.