2(3x + 4) = 4x + 16 find x

2y = 1/2(3y + 5) find y

d + 2 = 1/2(4d - 6) find d

4q - 2 = 2(3q - 6) find q

Can someone offer help?

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- Dec 14th 2010, 07:09 AMtysonrssfinding x
2(3x + 4) = 4x + 16 find x

2y = 1/2(3y + 5) find y

d + 2 = 1/2(4d - 6) find d

4q - 2 = 2(3q - 6) find q

Can someone offer help? - Dec 14th 2010, 07:10 AMe^(i*pi)
The Distributive law is used here. Can you expand the brackets?

- Dec 14th 2010, 07:14 AMtysonrss
Expand the brackets?

- Dec 14th 2010, 05:54 PMProve It
You should know that $\displaystyle \displaystyle a(b + c) = ab + ac$. See how what's on the outside has been multiplied by everything on the inside?

If you do that then that simplifies the problems greatly.

This is called "expanding the brackets". - Dec 14th 2010, 06:01 PMbigwave
- Dec 14th 2010, 06:07 PMpickslides
If the distributive law is not desired then as a first step for each

Q1. divide both sides by 2

Q2. times both sides by 2

Q3. times both sides by 2

Q1. divide both sides by 2 - Dec 14th 2010, 06:08 PMProve It
- Dec 14th 2010, 06:53 PMarccos
The idea of these problems is to get all of the unknown(in this case x) on one side and the numbers on the other.

Firstly , expand all the brackets.

This can be done by multiplying 2(the factor) into the bracket.

$\displaystyle = 6x + 8$ (nothing changes on the right side)

$\displaystyle 6x + 8 = 4x + 16 $

Now, 'move' the x to the left side and the 8 to the right side.

Subtract 8 and 4x from both sides.

$\displaystyle 6x +8 - 8 - 4x = 4x - 4x -8 + 16 $

$\displaystyle 2x = 8 $

$\displaystyle x = \dfrac{8}{2} = 4. $

Solve the other problems in the similar fashion. Hope this helps.