# Volumes

• July 4th 2007, 06:38 AM
Volumes
Two similar tins have heights 12cm and 20cm.
The volume of the smaller tin is 162cm^3.

Calculate the volume, in cm^3, of the larger tin.

I got the following, not sure if it's right:

20 divided by 12 is 1.67 , so this is the scale factor.
I did 162/12 to get get 13.5 and multiplied this by 1.67 to get 22.545.
22.545 * 20 (length of large tin) is 450.9cm^3.

Am I right?
• July 4th 2007, 06:45 AM
ThePerfectHacker
Quote:

$\left( \frac{20}{12} \right)^3 = \frac{V}{162}$
Solve for $V = 750 \mbox{ cm}^3$