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Thread: isoseles

  1. #1
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    isoseles

    Last edited by perash; Dec 20th 2007 at 09:26 AM.
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  2. #2
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    Let $\displaystyle N$ be the midpoint of $\displaystyle \overline{BE}.$

    We have

    $\displaystyle \overline{MN}\parallel\overline{BH}\implies\overli ne{NM}\perp\overline{AH}\implies\overline{AM}\perp \overline{HN}.$ Finally $\displaystyle \overline{HN}\parallel\overline{CE}\implies\overli ne{AM}\perp\overline{EC}~\blacksquare$
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