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Math Help - Circle

  1. #1
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    Circle

    A circle is inscribed into a rhombus abcd with one angle 60 degree.the distance from the centre of the circle to the nearest vertex is equal to 1.if p is any point on the circle then square(pa)+square(pb)+square(pc)+square(pd)
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  2. #2
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    Quote Originally Posted by prasum View Post
    A circle is inscribed into a rhombus abcd with one angle 60 degree.the distance from the centre of the circle to the nearest vertex is equal to 1.if p is any point on the circle then square(pa)+square(pb)+square(pc)+square(pd)
    Um... what is the question?

    Is it supposed to be: Prove that (\overline{PA})^2 + (\overline{PB})^2 = (\overline{PC})^2 + (\overline{PD})^2
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  3. #3
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    we have to find the value
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