the area of a rectangle of legthx is given by 3x^(2) + 5x. find the width of the rectangle Is this set up correct? 2x+2(3x^(2) +5x)= perimeter
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No! Let $\displaystyle y$ be the width. Then the area is $\displaystyle xy$. We have $\displaystyle xy=3x^2+5x\Leftrightarrow xy=x(3x+5)\Leftrightarrow y=3x+5$
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