Please help me with the following problem:
Write down the equation of a circle radius 2 and center (1,1). Find the points where this circle cuts the axes. Find the equation of the tangent to this circle at the point where it cuts the positive y-axis and find the point where this tangent cuts the x-axis.
Thx in advance
Hi Boz,
You have not replied to Skeeters post.Did you work it out? If not here are suggestions.
1 plot the circle
2Label as follows
A negative x intersection of circle
B positive x " " "
C negative y " " "
D positive y " " "
3 note the slope diagrams which can be formed by drawing radii to each intersection with appropriate horizontal or vertical lines
4 What are the properties of a 2-1 right triangle?
5 carry on
bjh
You will learn much better by doing it yourself rather than having someone else give you the "full solution". Skeeter told you that the equation of a circle with center at (h, k) and radius r is .
You are told that the center of this circle is at (1, 1) and its radius is 2. What is its equation?
That circle cuts the x-axis where y= 0 and the y-axis where x= 0. Put y= 0 in the equation and solve for x. Then put x= 0 and solve for y. (Do not multiply out the squares to solve the equations. You should be able to write them as and and take the square root of both sides.)
A tangent line is always perpendicular to the radius of the circle. What is the slope of the line from (1, 1) to the point where the circle cuts the positive x-axis? The slope of the tangent line is the negative of the reciprocal of that (-1/m). What is the equation of the tangent line? Set y= 0 in the equation of that tangent line and solve for x.