Given triangle ABC with AB > AC. The bisectors of the interior and exterior angles at A intersect line BC at points D and E, respectively.
((sqrt (AD^2+AE^2)) / CD) - (sqrt (AD^2+AE^2)) / BD = 2
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I haven't solve this yet, but I have some observations. . . .
The bisectors of an interior angle and its exterior angle are perpendicular. . . Hence: .
here's the pic ... http://yfrog.com/evhonorsproblem380p
Last edited by Kaloda; November 26th 2010 at 04:48 AM.
tnx ... that's what i need ...
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