a. Intercept theorem - Wikipedia, the free encyclopedia
b. BT=TS ==> PS/SQ = BT/TC=1 ==> PS=SQ, MOREOVER the triangles ATC & ATB have the same area, and so to triangles ASP & ASQ.
In the figure in the attachment
Given that line segment PQ is parallel to line segment BC.
part a, prove that ratio PS/SQ = BT/TC
part b, If line segment AT is a median in triangle ABC, what can be concluded from the proof in part a? Please explain this, thank you.
a. Intercept theorem - Wikipedia, the free encyclopedia
b. BT=TS ==> PS/SQ = BT/TC=1 ==> PS=SQ, MOREOVER the triangles ATC & ATB have the same area, and so to triangles ASP & ASQ.