Calculate the volume of a hemispherical object with a radius of 1.5cm - the volume of the ball which is submerged in the water?
I am not really sure what type of question is this. The question is below. Thank you.
A hollow hemispherical bowl of radius 4cm has a smaller solid spherical marble of radius 1cm at the bottom. If the bowl is filled with water to a depth of 1.5cm, find the volume of water in the bowl.
I would solve this problem with Calculus. The most important step is to know that given a hemisphere filled with water to depth of having radius then its volume is . Then from that your subtract the volume of the marble inside which in this case has volumeOriginally Posted by poppy_wolf
to make sure that I got your question I've attached a sketch of the situation as I understand it.
The marble has a diametre of 2 cm, that means it will stuck out of the water if there is only a depth of 1.5 cm.
Therefore you have to calculate two parts of spheres:
The difference of both volumes is the volume of water you're looking for.