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Math Help - Finding an area of a triangle:

  1. #1
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    Finding an area of a triangle:

    We have a square ABCD with sides = 1, and BE=1, and AE=CE.
    What is the area of triangle ABE?

    How can I solve this?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by thumpin_termis View Post
    We have a square ABCD with sides = 1, and BE=1, and AE=CE.
    What is the area of triangle ABE?

    How can I solve this?
    I found two ways to solve this and then stop. this is the shorter of the two methods. See the modified diagram below.

    from the description we see that \triangle AEC is isosceles. thus if we extend the line BE, it will cut the diagonal at a right angle. from this we can the angles that you see filled in.

    now we simply use the formula \mbox {Area} = \frac {1}{2}(BE)(AE) \sin 135^{ \circ} = \frac { \sqrt {2}}{4}





    if you have any questions say so. i was kind of rushing through this and didn't explain much
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