In a right triangle ABC, the legs are AB = 5 and BC = 12, and in the right triangle DEF, the hypotenuse is DE = 10, and EF = 8. Which is DF + AC? 19 15 13 12
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Originally Posted by sanee66 In a right triangle ABC, the legs are AB = 5 and BC = 12, and in the right triangle DEF, the hypotenuse is DE = 10, and EF = 8. Which is DF + AC? 19 15 13 12 In a right triangle the "legs" are the sides other than the hypotenuse, so in (by Pythagoras' theorem) . In we have the hypotenuse is , and leg , so: so: RonL
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