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Math Help - Triangle - proof

  1. #1
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    Triangle - proof

    Point M is the middle of side BC in acute triangle \Delta ABC. Point K lies on side BC in such a way that \angle BAM = \angle KAC. A point E was chosen on side AK such that \angle BEK = \angle BAC/ Show that \angle KEC = \angle BAC .

    I ask for your kind help in tackling this. I would attach a picture, but I will not, as I am not completely sure how to construct the given points so that it all hangs together.
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  2. #2
    MHF Contributor Unknown008's Avatar
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    Uh... there was the exact same question asked here.
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