# Math Help - Triangle - proof

1. ## Triangle - proof

Point $M$ is the middle of side $BC$ in acute triangle $\Delta ABC$. Point $K$ lies on side $BC$ in such a way that $\angle BAM = \angle KAC$. A point $E$ was chosen on side $AK$ such that $\angle BEK = \angle BAC$/ Show that $\angle KEC = \angle BAC$.

I ask for your kind help in tackling this. I would attach a picture, but I will not, as I am not completely sure how to construct the given points so that it all hangs together.

2. Uh... there was the exact same question asked here.