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Thread: isosceles triangle

  1. #1
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    isosceles triangle

    In the isosceles triangles ABC and CDE below, BC = 16 in., DE = 11 in. What is CD - AD?

    Here
    Last edited by ThePerfectHacker; Jun 22nd 2007 at 06:06 AM.
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  2. #2
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    Hello, sanee66!

    In the isosceles triangles $\displaystyle ABC$ and $\displaystyle CDE$ below,
    . . $\displaystyle BC = 16\text{ in.},\;DE = 11\text{ in.}$
    What is $\displaystyle CD - AD$?
    Code:
                A
                *
               *   *  D       11
              *       *   *   *   *   * E
             *           *           *
            *               *       *
           *                   *   *
        B *   *   *   *   *   *   * C
                     16
    We have: .$\displaystyle AC \:=\:BC\:=\:16$
    . . . .and: .$\displaystyle DC \:=\:DE\:=\:11$

    Hence: .$\displaystyle AD \;=\;AC - DC \;=\;16 - 11\;=\;5$

    Therefore: .$\displaystyle CD - AD\;=\;11 - 5 \;=\;6$

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