In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles? 16/2 18/2 32/2 36/2

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Originally Posted by sanee66 In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles? 16√2 18√2 32√2 36√2 Hello, if the legs of an isosceles right triangle is a then the hypotenuse c is calculated by: $\displaystyle c = a \cdot \sqrt{2}$ Therefore the sum of the two hypotenuses is: $\displaystyle s = 12 \cdot \sqrt{2} + 24 \cdot \sqrt{2} = 36 \cdot \sqrt{2}$

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