1. ## hypotenus problem?

In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles?

16/2
18/2
32/2
36/2

2. Originally Posted by sanee66
In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles?

16√2
18√2
32√2
36√2
Hello,

if the legs of an isosceles right triangle is a then the hypotenuse c is calculated by:

$c = a \cdot \sqrt{2}$

Therefore the sum of the two hypotenuses is:

$s = 12 \cdot \sqrt{2} + 24 \cdot \sqrt{2} = 36 \cdot \sqrt{2}$