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Thread: hypotenus problem?

  1. June 20th 2007, 04:15 PM #1
    sanee66
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    hypotenus problem?

    In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles?

    16/2
    18/2
    32/2
    36/2
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  2. June 20th 2007, 09:10 PM #2
    earboth
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    Quote Originally Posted by sanee66 View Post
    In the isosceles right triangles ABC and MNP, AB = BC = 12 and MN = NP = 24. Which is the sum of the hypotenuses of these triangles?

    16√2
    18√2
    32√2
    36√2
    Hello,

    if the legs of an isosceles right triangle is a then the hypotenuse c is calculated by:

    c = a \cdot \sqrt{2}

    Therefore the sum of the two hypotenuses is:

    s = 12 \cdot \sqrt{2} + 24 \cdot \sqrt{2} = 36 \cdot \sqrt{2}
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