A plane P passes trough the points (1,1,1) and (2,0,3) And it is perpendicular to the plane Q x+2y-3z=0 What is the equation for plane P? Please help!
Follow Math Help Forum on Facebook and Google+
Originally Posted by techmath A plane P passes trough the points (1,1,1) and (2,0,3) And it is perpendicular to the plane Q x+2y-3z=0 is the vector determined by the two points. So the normal to the needed plane is cross product .
View Tag Cloud