Q. I is the incentre of a triangle ABC. P is the point of intersection of the angle bisector AI of the angle at A and the circumcircle of the triangle other than A.

Prove that PB = PC = PI.

Printable View

- Oct 20th 2010, 03:12 AMakshay1995related to triangles and circles
Q. I is the incentre of a triangle ABC. P is the point of intersection of the angle bisector AI of the angle at A and the circumcircle of the triangle other than A.

Prove that PB = PC = PI.