Q. I is the incentre of a triangle ABC. P is the point of intersection of the angle bisector AI of the angle at A and the circumcircle of the triangle other than A.

Prove that PB = PC = PI.

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- October 20th 2010, 03:12 AMakshay1995related to triangles and circles
Q. I is the incentre of a triangle ABC. P is the point of intersection of the angle bisector AI of the angle at A and the circumcircle of the triangle other than A.

Prove that PB = PC = PI.