Three points have coordinates A(-2,-1), B(10,6) and C(a,-6). Given AB=BC find the possible values of a. If the figure ABCD is a rhoMbus, find the coordinates of D.
Three points have coordinates A(-2,-1), B(10,6) and C(a,-6). Given AB=BC find the possible values of a. If the figure ABCD is a rhoMbus, find the coordinates of D.
Since AC= BC, we must have . Subtracting from both sides leaves .
The vector BC= <a, -6>- <10, 6>= <a- 10-, -12> is parallel to the vector AD. Find the coordinates of D by add BC to the corodinates of A.