Given a convex quadrilateral, construct a triangle whose area is the same as the area of the quadrilateral.
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Originally Posted by MATNTRNG Given a convex quadrilateral, construct a triangle whose area is the same as the area of the quadrilateral. Well, if you know the quadrilateral's area, simply construct a right triangle where the legs are a and b, such that ab/2 = quad's area
Originally Posted by MATNTRNG Given (where?) a convex quadrilateral, construct a triangle whose area is the same as the area of the quadrilateral. 1. Draw a diagonal BD. Produce the side AB. 2. A parallel to BD through C crosses the line (AB) in C'. The triangle BDC' has the same area as triangle BDC. 3. Thus triangle AC'D has the same area as the quadrilateral ABCD.
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