# Thread: Calculating an x,y intercept point

1. ## Calculating an x,y intercept point

I need to know how to calculate the values for mx and my for the attached image. I am a novice. Any help would be appreciated.

2. Originally Posted by questforknowledge004
I need to know how to calculate the values for mx and my for the attached image. I am a novice. Any help would be appreciated.

mx = 150
my = 150

Do you need to see all of the work involved (Equation of a line, Slope, ect.)?

3. Yes. Please, I need to see all of the work. All of the calcuations involved. I am a novice.

Thanks

RE:

Part #1

5. ## Re:

RE:

Part #2

6. The more analytic way of doing this once you get the two eqautions follows.

We have the equations of the two lines from qbkr21:
$y = x$
$y = -x + 300$

These lines have different slopes and will thus intersect at a point. The point satisfies BOTH line equations. So the two x values in the two equations are the same and the two y values in the two equations are the same. So since y = y...

$x = -x + 300$

$2x = 300$

$x = 150$

We can now substitute this x value into either line equation and find that
$y = 150$

So the coordinates of your point of intersection is $(x, y) = (150, 150)$

-Dan